Exam 4 (2)

Navigation » List of Schools » West Los Angeles College » Biology » Biology 006 – Genera Biology I » Spring 2021 » Exam 4 (2)

Need help with your exam preparation?

Existing Quiz Clients Login here

Below are the questions for the exam with the choices of answers:

Try The Exam

Question #1

You breed a black, long-haired rabbit with a white, short-haired rabbit. All of the offspring have long, black hair. If the genes for hair color and length are closely linked on the same chromosome, what would you expect to see in the F2 generation?

A 15 black, long-haired: 1 black, short-haired: 1 white, long-haired: 13 white, short-haired

B All long-haired black

C 3 black, long-haired: 1 white, short-haired

D 3 black, long-haired: 9 black, short-haired: 9 white, long-haired: 1 white, short-haired

E 9 black, long-haired: 3 black, short-haired: 3 white, long-haired: 1 white, short-hairedite, short-haired

Question #2

A horticulturist is breeding another variety of houseplant in which two genes control leaf color. G (allele for green) is dominant to g (yellow) and B (second allele for green) is dominant to b (yellow). In this plant variety, if the two genes are homozygous recessive, then the plant is yellow. Both genes need to be dominant in order for the green color to be produced. However, if only one of these two genes is dominant, then both pigments can be produced. Two plants are crossed and a green and yellow plant is produced. Which of the genotypes listed below could apply to this green and yellow plant?

A GGBb

B Ggbb

C ggBb, Ggbb

D GGBB

E ggBb, GGBb

F GgBb

Question #3

During prometaphase, the sister chromatids organize into a single row in the center of the cell.

A TRUE

B FALSE

Question #4

Polyploidy in plants

A allows for adaptation to diverse environments.

B All of these statements are true regarding polyploidy in plants.

C allows humans to create plants with unusual flowers.

D may alter the levels of gene expression.

E is very common.

Question #5

In rabbits, spotted coat (S) is dominant to solid color (s) and black (B) is dominant to brown (b). A true-breeding black spotted rabbit is mated to a true-breeding brown solid rabbit to produce a heterozygous F1 generation. Two F1 individuals are mated, and you do not see the typical 9:3:3:1 ratio of offspring, so you take an F1 rabbit and perform a test cross. Instead of the expected ratio, you see that most progeny look like the parental rabbits but a few are new, unique phenotype. This tells you that:

A that the genes for fur pattern and fur color are on the same chromosomes

B that the genes for fur pattern and fur color are epistatic

C that the genes for fur pattern (spotted vs. non-spotted) and fur color assort independently

D that fur pattern and fur color are maternally inherited

E that the genes for fur pattern and fur color are on different chromosomes

Question #6

Imagine that fur length in a chinchilla species is a trait controlled by at least three genes. For each of these genes, short fur (PS, QS, RS) has incomplete dominance over long fur (PL, QL, or RL). A chinchilla homozygous for short fur is test-crossed with a chinchilla with long fur. What will be true of their offspring?

A 1/4 will be homozygous for long fur, 1/4 will be homozygous for short fur, and 1/2 will be heterozygous

B All of their offspring will have long fur

C All of their offspring will have intermediate-length fur

D 1/2 of their offspring will have long fur, 1/2 of their offspring will have short fur

E 1/2 of their offspring will be homozygous for long fur, 1/2 of their offspring will be homozygous for short fur

Question #7

Gregor Mendel:

A was a monk and carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

B was a monk, discovered the basic principles of hereditary, carried out his experiments in an abbey garden, and carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

C conducted research that proved that the “blending hypothesis” was the correct explanation of how heredity worked.

D carried out his experiments on heredity by doing thousands of genetic crosses on a common garden plant.

E discovered the basic principles of hereditary.

F carried out his experiments in an abbey garden.

Question #8

The H substance is needed for the proper phenotypic expression of the A, B, and AB blood types in the ABO blood typing system in humans. Individuals who are recessive for the H substance (hh) will have a type O phenotype, even if they have the A and/or B alleles. Two individuals, each with type AB blood and heterozygous at the H locus have children. What is the probability they will have a child who is phenotypically type O?

A 4/16

B No chance

C 100%

D 6/16

E 3/16

Question #9

The inheritance pattern in which the mother provides gene products to the developing egg cells is called

A genomic imprinting.

B maternal inheritance.

C linkage.

D X inactivation.

E extranuclear inheritance.

Question #10

Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene – an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). How many eyelash length alleles does an individual have in one of her/his somatic cells?

A 23

B 2

C 1

D 46

E 3

Question #11

Which of the following is not a characteristic of an X-linked recessive disorder pedigree?

A If a female has the trait, her father must also have it.

B The characteristic often skips a generation.

C More females than males are affected.

D If a woman has the characteristic, all of her sons will have it.

E An affected son can have normal parents.

Question #12

Meiosis I produces ________, and meiosis II produces ________ cells.

A two somatic, two gametic

B two haploid, 4 haploid

C two diploid, two haploid

D two diploid, 4 haploid

E two haploid, two haploid

Question #13

P, D, and Q are three genes found on a single chromosome in greyhounds. The recombination frequencies between the three genes are shown below. In which order are these genes found on the greyhound chromosome? P – D = 50%; P – Q = 20%; D – Q = 30%

A It is impossible to determine.

B Q-D-P

C P-Q-D

D P-D-Q

E D-P-Q

Question #14

A gene for sweat gland production is located on the X chromosome. A man who lacks sweat glands marries a woman who has normal sweat glands. Which of the following are possible phenotypes of their children?

A The boys will be mosaic; they will have patches of skin with sweat glands and patches of skin lacking sweat glands.

B The girls will be mosaic; they will have patches of skin with sweat glands and patches of skin lacking sweat glands.

C All of the boys will lack sweat glands.

D Half of the girls will have sweat glands and half of the girls will lack sweat glands.

E Half of the boys will have sweat glands and half of the boys will lack sweat glands.

Question #15

Which of the following traits would not be considered multi-factorial?

A ABO blood type

B alcoholism

C suicide risk

D diabetes

E cleft lip/palate

Question #16

In birds, sex is determined by a ZW chromosome scheme. Males are ZZ and females are ZW. A lethal recessive allele that causes death of the embryo is sometimes present on the Z chromosome in pigeons. What would be the sex ratio in the offspring of a cross between a male that is heterozygous for the lethal allele and a normal female?

A 1:2 male to female

B 3:1 male to female

C 2:1 male to female

D 4:3 male to female

E 1:1 male to female

Try The Exam

Fresh Grad Lands Job as Real Estate Agent With Help from Professional Writers

Need help with your exam preparation?

Below are the questions for the exam with the choices of answers:

Christian S.

Tyra

Linda

Manush

We accept payment